Whats the distance between (-8,-7) (8,-4)

1 answer:

8 0

To find the distance between points, use the distance formula.

Distance formula: $\sqrt{ (x_{2} - x_{1})^{2} + ( y_{2} - y_{1})^{2} }$

Plug in your values for $x_{2}, x_{1}, y_{2}, y_{1}$ using (-8, -7) and (8, -4) and solve.

$\sqrt{(8 - (-8))^{2}+(-4 - (-7))^{2}}$
$\sqrt{(8+8)^{2}+(-4+7)^{2}}$
$\sqrt{(16)^{2}+(3)^{2}}$
$\sqrt{256+9}$
$\sqrt{265}$ ≈ $16.28$

Answer:
Approximately 16.28 units.

You might be interested in

Mr Ruiz drove 305 miles in 5 hours on Saturday and 190 miles in 4 hours on Sunday what is his average speed in miles per hour fo

Snezhnost [94]

Add the mileage together to find total miles.

Add the hours together.

Divide total miles by total hours.

305 + 190 = 495 miles

5 + 4 = 9 hours.

495 / 9 = 55 miles per hour.

The average speed was 55 miles per hour.

4 0

3 years ago

A baby weighed 7.25 pounds at birth. At the end of 8 months, the baby weighed 212

Vinil7 [7]

Answer:

1537pounds

Step-by-step explanation:

Given parameters:

Weight of baby at birth = 7.25 pounds

Unknown:

Weight at the end of 8months = ?

Solution:

From the second sentence;

Weight at the end of the eighth month = 212 x weight at birth.

Input the parameters and solve;

Weight at the end of eighth month = 212 x 7.25 = 1537pounds

7 0

4 years ago

Is 3:4 equivalent to 12:24

Nuetrik [128]

No because 3 times 4 is 12 but 4 times four is 16 and TO get from 4 to 24 you multiply 6 but 6 times 3 is 18 so no I think

3 0

4 years ago

Read 2 more answers

What is the focus of the parabola given the equation y=x^2+4x-1

IrinaK [193]

Let's first rewrite it in vertex form.
Start by completing the square.
y = x² + 4x + 4 - 4 - 1
y = (x + 2)² - 5
(x + 2)² = y + 5

Now, 4a = 1; a = $\frac{1}{4}$

So, the vertex form is (x + 2)² = 4( $\frac{1}{4}$ )(y + 5)
So, we know that the vertex is at (-2, -5).
Since it's a concave up parabola, we just have to change the y-value to find the focus.

∴ F(-2, -5 + $\frac{1}{4}$ )
F(-2, $\frac{-19}{4}$ )