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3 years ago

Whats the distance between (-8,-7) (8,-4)

1 answer:

8 0

To find the distance between points, use the distance formula.

Distance formula: $\sqrt{ (x_{2} - x_{1})^{2} + ( y_{2} - y_{1})^{2} }$

Plug in your values for $x_{2}, x_{1}, y_{2}, y_{1}$ using (-8, -7) and (8, -4) and solve.

$\sqrt{(8 - (-8))^{2}+(-4 - (-7))^{2}}$
$\sqrt{(8+8)^{2}+(-4+7)^{2}}$
$\sqrt{(16)^{2}+(3)^{2}}$
$\sqrt{256+9}$
$\sqrt{265}$ ≈ $16.28$

Answer:
Approximately 16.28 units.

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Sams brother is 7 years older than Sam. His mother is 4 less than 3 times sams age. Their combined age is 63. How old isn’t Sam,

statuscvo [17]

The answer is 14. This is because 63=3+x+3x-4. Then You just subtract it and then you get 64=4x. Then you just divide it and then you get x=16.

4 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

PLEASEEEE

belka [17]

Answer:

The answer to your questions is: 25 new teachers

Step-by-step explanation:

Data

# of students = 2000

ratio = 3:80 teachers to students

New teachers = ?

Process

I suggest to use rule of three to solve this problem

3 teachers ---------------- 80 students

x ---------------- 2000 students

x = (2000 x 3) / 80 = 75 teachers

Number of initial teachers = 75

The ratio change to 1:20

1 teacher ------------------- 20 students

x ------------------- 2000 students

x = (2000 x 1) / 20

x = 100 teachers

Number of new teachers = 100 - 75 = 25

3 0

4 years ago

Which statements about the graph of the function f(x) = -2- 4x + 2 are true? Select three options

soldi70 [24.7K]

Answer:Its B,C, and E man

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Como soluciono equaciones =0

Rom4ik [11]

Step-by-step explanation:

ما زلت لا أستطيع أن أخبرني بما تحاول أن تخبرني به ولد أو بنت آسف على تحمله

8 0

3 years ago