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Iteru [2.4K]
3 years ago
15

A bag contains 4 blue marbles, 5 green marbles and 3 yellow marbles. How many blue marbles should you add to the bag so that the

probability of drawing a marble is 0.80
Mathematics
1 answer:
Nadusha1986 [10]3 years ago
4 0

Answer:

ADD 28 blue marbles.  Added for total of 32/40= 0.80

Step-by-step explanation:

4/12 or 1/3 (33%) for original amount

X/X+8=.8

X=.8 x (X+8)

X=

<u>Sorry </u>I do not remember how to complete this equation so did it by substituting numbers until solution was .80

Need a total of 32/32+8 (40)  =0.8  or 80% chance

So need to add

28 blue marbles.

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Answer:

Option 2 i.e. 9√2 is the correct option.

Step-by-step explanation:

Given the expression

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Therefore, we need to solve the expression such as

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\sqrt{128}=\sqrt{64\times 2}=\sqrt{8^2\times \:2}=8\sqrt{2}

so the expression becomes

\frac{\left(\sqrt{200}\:+\:\sqrt{128}\:\right)}{2}=\frac{10\sqrt{2}+8\sqrt{2}}{2}

Add similar elements:  10\sqrt{2}+8\sqrt{2}=18\sqrt{2}

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Divide the numbers: 18/2 = 9

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Therefore, we conclude that:

\frac{\left(\sqrt{200}\:+\:\sqrt{128}\:\right)}{2}=9\sqrt{2}

Hence, option 2 i.e. 9√2 is the correct option.

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