Square root of 10 plus the square root of 5
%7D%20" id="TexFormula1" title=" \sqrt{10} + \sqrt{5 } " alt=" \sqrt{10} + \sqrt{5 } " align="absmiddle" class="latex-formula">
1 answer:
Hello Harrisonkaden13, the <span>square root of 10 plus the square root of 5 is,
</span>
<span>Answer:
</span>The principal, real, root of:
<span>^2√10</span><span> = 3.16227766 </span>All roots:
3.16227766 or <span>−3.16227766</span>
10 is not a perfect square.
The principal, real, root of:
^2<span>√5 </span><span>= 2.23606798</span>All roots:
2.23606798 or <span>−2.23606798
</span>5 is not a perfect square
We add them and we get 5.39834564 or -5.39834564.
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x=9.43
Step-by-step explanation:
I used the Pythagorean theorem.
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In step 2 the 6(1 * x) is supposed to be 6 * 6x.
Answer:
{-0.36, 8.36) to the nearest hundredth.
Step-by-step explanation:
x^2 - 8x = 3
(x - 4)^2 - 16 = 3
(x - 4)^2 = 19
Taking square roots:
x - 4 = +/- √19
x = 4 +/- √19
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Answer:
Step-by-step explanation:
x = (y-4)^2 - 2
square root of x = y - 4 - 2
square root of x = y - 6
(square root of x) - 6 = y
