Answer:
see below
Step-by-step explanation:
1) see attached image
2) <u> bearings from A to B</u>
Note: bearing is always clockwise from A and from North.
(i)
bearing 180° + 67°
247° from N
(ii)
bearing 148 + 180
328° from N
(iii)
bearing 180 - 21
159° from N
(iv)
39° from N
(v)
bearing 90 - 40
50° from N
3) <u>back bearing from each diagram on no. 2</u>
<u />
Note: subtract 200 if bearing is more than 180
add 180 if the bearing is less than 180
(i) 247 - 200 = 47°
(ii) 328 - 200 = 128°
(iii) 159 + 180 = 339°
(iv) 39 + 180 = 219°
(v) 50 + 180 = 230°
Given:
The equation of a line is
To find:
The slope and y-intercept of the line.
Solution:
We have,
...(i)
The slope intercept form of a line is
...(ii)
Where, m is the slope and b is the y-intercept.
On comparing (i) and (ii), we get
Slope of the line = 1
y-intercept of the line = -4
The coordinate form of y-intercept is (0,b). So, the y-intercept of the given line is (0,-4).
Therefore, the slope of the line is 1 and the y-intercept is (0,-4).
She farts at least 20 juuls
Answer:
Step-by-step explanation:
You need an image for problem to be solved, please repost it with a image, so it can be solved
Answer:
(6 - 8t)(6t - 4t²) / ((6t - 4t²)² + 64)⁰‧⁵
