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Arada [10]
2 years ago
6

Write what comes next in the pattern 1.2,2,4,4.8,9.6??

Mathematics
2 answers:
Dahasolnce [82]2 years ago
5 0
Ok so I believe it’s 10.4 because first it’s

1.2 + 0.8 = 2
2 * 2 = 4
4 + 0.8 = 4.8
4.8 * 2 = 9.6

So 9.6 + 0.8 = 10.4
MrRissso [65]2 years ago
4 0

Answer:

19.2

Step-by-step explanation:

each element of the pattern is the product of the previous element and 2

1.2 x 2 = 2.4

2.4 x 2 = 4.8

4.8 x 2 = 9.6

therefore, the next number in the pattern would be the last element multiplied by 2

9.6 x 2 = 19.2

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Please help i d k if its -128 or -1/128
7nadin3 [17]

Answer:

\frac{ {y}^{ - 5} }{x {}^{ - 3} }  \\

when x is 2, y is -4

=  \frac{ {( - 4)}^{5} }{ {2}^{ - 3} }  \\  \\  =   - 1024 \times  {2}^{3}  \\  =  - 1024 \times 8 \\  =  - 8192

None of the objectives is right

7 0
3 years ago
An arc subtends a central angle measuring \dfrac{\pi}{2}
Agata [3.3K]

Arc Length is 1/4th of the circumference .

<u>Step-by-step explanation:</u>

Here we need to find fraction of the circumference is this arc when An arc subtends a central angle measuring \dfrac{\pi}{2} radians ! Let's find out :

We know that circumference of an arc subtending a central angle of x is :

⇒ Arc = \frac{Angle}{360}(2\pi r)

⇒ Arc = \dfrac{\frac{\pi}{2}}{360}(2\pi r)

⇒ Arc = \frac{90}{360}(2\pi r)

⇒ Arc = \frac{90}{90(4)}(2\pi r)

⇒ Arc = \frac{1}{4}(2\pi r)

⇒ Arc = \frac{1}{4}(Circumference)

Therefore , Arc Length is 1/4th of the circumference .

4 0
3 years ago
Which property justifies the procedure used to eliminate fractions and decimals from equations?
igor_vitrenko [27]
By multiplying both sides of an equation by a number, you can eliminate all decimals and fractions, so the answer is C.
4 0
3 years ago
My sisters spring break packet for math , she didn't do it . I am trying to help her but i just don't feel like explaining it to
Mariana [72]
60 - 18 = 42 

The answer is 42 yards of fabric. :)
3 0
3 years ago
A tennis player moves in a straight-line path as shown in the figure below. find her average velocity in the following time inte
Andreyy89
To find the average velocity in a velocity-time graph at a particular interval, simply determine the gradient at that particular interval. 

<span>a. average velocity= 4/1 </span>
<span>= 4m/s </span>

<span>b. average velocity from 1 to 2.5s= 6/(2.5-1) </span>
<span>= 4m/s </span>

<span>average velocity from 2.5 to 4.0s= 0m/s </span>

<span>average velocity from 0 to 4.0s= (4+0)/4 </span>
<span>= 1m/s </span>

<span>c. average velocity from 1.0 to 4.0s= (4/3)m/s </span>

<span>average velocity from 4.0 to 5.0s= 2/1 </span>
<span>= 2.0m/s </span>

<span>average velocity from 1.0 to 5.0s= ((4/3)+2)/4 </span>
<span>= (5/6)m/s </span>

<span>d. average velocity from 0 to 4.0s= 1.0m/s </span>

<span>average velocity from 4.0 to 5.0s= 2.0m/s </span>

<span>average velocity from 0 to 5.0s= (1.0+2.0)/5 </span>
<span>= (3/5)m/s </span>
4 0
3 years ago
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