Answer:
We have 2.58 moles toluene in solution
Explanation:
Step 1: Data given
Mass of toluene = 801 grams
Boiling point of the solution = 90.3 °C
Boiling point elevation constant = 2.92 °C/m
Boiling point temperature = 80.9 °C
Step 2: Calculate molality
ΔT = i*Kb*m
⇒with ΔT = the boiling point elevation = 90.3-80.9 = 9.4 °C
⇒with i = the van't Hoff factor = 1
⇒with Kb = the Boiling point elevation constant = 2.92 °C/m
⇒with m = the molality
m = 9.4 °C / 2.92
m = 3.22 molal = moles / kg
Step 3: Calculate moles toluene
Molality = moles tolune / mass cyclohexane
3.22 molal = moles toluene / 0.801 kg
Moles toluene = 2.58 moles
We have 2.58 moles toluene in solution