Answer:
The answer to your question is: 0.0265 moles of H3PO4
Explanation:
Data
[H3PO4] = ?
Volume Ba(OH)2= 0.186 l
[Ba(OH)2] = 0.214 M
Equation
2H3PO4 (aq) + 3 Ba(OH)2 (aq) ---> 6H2O (l) + Ba3(PO4)2 (s)
Process
Molarity = moles / volume
moles = Molarity x volume
moles of Ba(OH)2 = 0.214 x 0.186
= 0.0398
Rule of three
2 moles of H3PO4 -------------------- 3 moles of Ba(OH)2
x -------------------- 0.0398 moles of Ba(OH)2
x = (0.0398 x 2) / 3
x = 0.0265 moles of H3PO4
Answer:
The answer to your question is number 2. NaNO₃ + H₂O
Explanation:
The reaction that is represented in this problem is an acid-base reaction. An acid-base reaction is a double displacement reaction.
The cation of a reactant attaches to the anion of the other reactant and viceversa.
Reactants NaOH and HNO₃
Cations Na⁺ H⁺
Anions OH⁻ NO₃⁻
Following the previous rule
Products NaNO₃ + H₂O
The products are a salt and water.
Releases heat
(Exothermic)
PH = -lg[H+]
pH = -lg[6.38·10-6] = 5.2