I need help on this i dont know whar to do
1 answer:
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Draw ΔABC as shown in the figure below.
m∠B = 137°, b = 14, c = 9.
From the Law of Sines,
sin(C)/c = sin(B)/b
or
sin(C)/9 = sin(137°)/14
sin(C) = (9/14)*sin(137°) = 0.4384
m∠C = arcsin(0.4384) = 26°
Because the sum of angles in a triangle is 180°, therefore
m∠A = 180 -137 - 26 = 17°
From the Law of Sines,
a/sin(A) = b/sin(B)
or
a/sin(17°) = 14/sin(137°)
a = (sin(17°)/sin(127°))*14 = 6
Answer:
The solution for the triangle is
a = 6, b = 14, c = 9
m∠A = 17°, m∠B = 137°, m∠C = 26°
m∠B = 137°, b = 14, c = 9.
From the Law of Sines,
sin(C)/c = sin(B)/b
or
sin(C)/9 = sin(137°)/14
sin(C) = (9/14)*sin(137°) = 0.4384
m∠C = arcsin(0.4384) = 26°
Because the sum of angles in a triangle is 180°, therefore
m∠A = 180 -137 - 26 = 17°
From the Law of Sines,
a/sin(A) = b/sin(B)
or
a/sin(17°) = 14/sin(137°)
a = (sin(17°)/sin(127°))*14 = 6
Answer:
The solution for the triangle is
a = 6, b = 14, c = 9
m∠A = 17°, m∠B = 137°, m∠C = 26°
let's recall the vertical line test, it's a function if when dropping a vertical line on the graph, it only touches it once on the way down.
Check the picture below.
