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Effectus [21]
3 years ago
12

I need help on this i dont know whar to do

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0
For 14-(-10), it’s pretty much like adding 14+10. So add 14+10 together, and that would be your answer, for example; let’s say it’s 13-(47). The answer would be 80, because it’s like adding 13+47. Number 3 is just like number one. I’m really sorry I don’t know how to do 4, 5, and 6 :)

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HELPPPPPPPPPPPPPppppppppp number 4
astraxan [27]

Answer:

3 dots

Step-by-step explanation:

This should be correct due to there only being 3 100% on the table

7 0
3 years ago
Simplify: j + 5 + 5c
irina [24]
The answer is 5
c
+
j
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5
5 0
2 years ago
A rectangle has a width represented by the expression 2y and a length represented by 12y - 5. which expression represents the ar
docker41 [41]

Correct option is B. Area of rectangle is 24y^{2} - 10 y

We know that area of rectangle = Length × Width

We are given,

Length = 12y - 5

Width = 2y

So, area of rectangle = (12y - 5) × (2y)

=   (12y - 5) × (2y)

=   (12y ×  2y) - (5 × 2y)

=   24 y^{2} - 10 y

<h3>What are algebraic equations?</h3>

An algebraic equation can be defined as a mathematical statement in which two expressions are set equal to each other. The algebraic equation usually consists of a variable, coefficients and constants. Also Check: Algebraic Expressions. In simple words, equations mean equality i.e. the equal sign.

To learn more about algebraic equations from the given link

brainly.com/question/11516438

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6 0
1 year ago
20. Factor the expression. ^2 + 7 + 12
neonofarm [45]

Answer: x^2 + 19

Step-by-step explanation: Cancel out x^2 and add 7 and 12 together. 7 + 12 = 19. Next plug in x^2. So, its now x^2 + 19.

Hope this help!

7 0
3 years ago
Read 2 more answers
The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?
Lilit [14]

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0
3 years ago
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