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Ludmilka [50]
2 years ago
13

PLEASE HELP ILL MARK BRAINEST!!!!

Mathematics
2 answers:
earnstyle [38]2 years ago
6 0

Answer:

(-3,8) would NOT fit the table.

Oksanka [162]2 years ago
6 0

Answer: (-3,8)

Step-by-step explanation: click on the file

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Solve the equation x^2-4x+85=0
lara [203]
Can't factor
use quadratic
for
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
1x^2-4x+85=0
a=1
b=-4
c=85

x=\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}
x=\frac{4+/- \sqrt{16-340} }{2}
x=\frac{4+/- \sqrt{-324} }{2}
x=\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}
remember that √-1=i
x=\frac{4+/- i(\sqrt{324}) }{2}
x=\frac{4+/- i(18) }{2}
x=2+/-9i

x=2+9i or x=2-9i
3 0
3 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
4 more than the quotient of 7 and m
tangare [24]

Answer:

4+ 7/m

Step-by-step explanation:

there might be parentheses but this is what the expression  would look like

3 0
3 years ago
Read 2 more answers
According to the box and whisker plot, what percent of contestants ate less than 15 hotdogs
Vesnalui [34]

Answer:

I believe that your answer would be C) 75%.

Step-by-step explanation:

Hope this helps!

=)

6 0
2 years ago
Solve for x.<br><br>x = ___<br><br>27<br>33<br>30​
kirill [66]
The answer is Answer 30 i think
4 0
2 years ago
Read 2 more answers
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