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2 years ago

(3,-2);slope 1/3 what is the answer?

Mathematics

1 answer:

wolverine [178]2 years ago

5 0

Answer:

y = $\frac{1}{3}$ x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{1}{3}$ , then

y = $\frac{1}{3}$ x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = 1 + c ⇒ c = - 2 - 1 = - 3

y = $\frac{1}{3}$ x - 3 ← equation of line

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Two third plush one half

Virty [35]

Two-thirds and one half is one and one sixth.

First, you times to denominators,

Then, you times the top by the bottom across, NOT BOTTOM!

Lastly, you add the top together then simplify, to get one and one sixth as your answer!

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3 years ago

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He price of a dozen eggs was $1.63. The price rose m dollars. Then the price dropped $0.12 per dozen. Express the current price

kherson [118]

Answer:

Step-by-step explanation:

because 1.63-.12 = 1.51 and m is the price and it is asking the current price which is 1.51 and then say the price m= {$1.51}

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3 years ago

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Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

2 years ago

How much warmer is 12°C than -20°C?

zvonat [6]

To put it simply, 12 degrees C is 12 away from 0 and -20 degrees C is 20 away from 0. Taking these two inputs and adding them together should give you 32. So 12 degrees C is 32 degrees warmer than -20 degrees C

8 0

2 years ago

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What is the square root of 49 multiplied by the square root of 9

fiasKO [112]

First we need to find the the answer to both the square root of 49 and 9.

The "square root" is a term referring to a number, multiplied by itself (x • x) would be = to your square root.

So for example: Square root of 16 = 4 because 4*4=16

So lets get out numbers:

$\sqrt{9} =3
$
$\sqrt{49}=7$

Now you multiply 3*7 (or 7*3) and you get 21.

Final answer: 21

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2 years ago

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