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Free_Kalibri [48]
3 years ago
15

Help!!! I'm stuck on this

Mathematics
1 answer:
Mariana [72]3 years ago
8 0
So c=3 years old and a= 25 ml (dose of adults)
so dose of child P=(3/3+12)*25=3/15*25=5 ml
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Y=3/2x+2 <br> 5x-y=5<br> At what point do they meet?
RSB [31]
(2,5) ...........................................................................................
7 0
3 years ago
Please help. I don't understand how to do this. I need this asap. please
Schach [20]

9514 1404 393

Answer:

  r = 1/9

Step-by-step explanation:

First of all, solve the equation for r:

  y = rx

  y/x = r . . . . . . . divide by x

__

Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.

  r = y/x = 5/45

  r = 1/9 . . . . . . . . . reduced fraction

_____

<em>Additional comment</em>

It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:

  y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value

6 0
3 years ago
Which of the following situations is best represented by the equation y = 15x ?
IrinaK [193]

Answer:

B.) There were 15 more questions on the test than the last test.

Step-by-step explanation:

4 0
3 years ago
A diagnostic test for a disease is such that it (correctly) detects the disease in 90% of the individuals who actually have the
Ne4ueva [31]

Answer:

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test positive

Event B: Has the disease

Probability of a positive test:

90% of 3%(has the disease).

1 - 0.9 = 0.1 = 10% of 97%(does not have the disease). So

P(A) = 0.90*0.03 + 0.1*0.97 = 0.124

Intersection of A and B:

Positive test and has the disease, so 90% of 3%

P(A \cap B) = 0.9*0.03 = 0.027

What is the conditional probability that she does, in fact, have the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.027}{0.124} = 0.2177

0.2177 = 21.77% conditional probability that she does, in fact, have the disease

3 0
3 years ago
Solve for w in P = 2w + 2l, if P = 38 and l = 12.
vova2212 [387]
W= 7

38=2w+2(12)
                /
38=2w + 24
-24        -24

14=2w
divid by 2    divid by 2

7=w
4 0
3 years ago
Read 2 more answers
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