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3 years ago

Identify the median for the data summarized on the boxplot.

Mathematics

2 answers:

LuckyWell [14K]3 years ago

7 0

Answer:

a.17.5

Step-by-step explanation:

icang [17]3 years ago

3 0

Answer:

C. 23.5

Step-by-step explanation:

The median is the line in the middle of the inside of the box.

If we locate the line in the middle of the box, we can see that it is above the number 23.5.

Therefore, the median of this box plot is 23.5 and the correct answer is choice C.

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Factor the expression using the GCF 42-12

Monica [59]

6(7 - 2)
6(5)

Check:
7*6 = 42
2*6 = 12
42-12 = 30 = 6(5) :)

5 0

3 years ago

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

What is the answer? I don’t understand how to get it.

miss Akunina [59]

Answer:

Step-by-step explanation:

Sub in the (x,y) points given into the equation to see if true ....you'll find A is the answer

Example point (3,95 ) 95 = -10.375 (3) + 126.125 ??

95 = 95 Check !

then try the other point ( 11,12) to be sure ....

5 0

2 years ago

Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a red mar

swat32

Assuming that each marble can be picked with equal probability, we notice that there is a total of

$4+2+5+1+7 = 19$

marbles, of which 2 are red.

So, the probability of picking a red marble is

$\dfrac{2}{19}$

In fact, as in any other case of (finite) equidistribution, we used the formula

$P(\text{event}) = \dfrac{\text{number of favourable cases}}{\text{number of all possible cases}}$

4 0

3 years ago

Evaluate b – 2a – c for a = –3, b = 9, and c = –6.

telo118 [61]

<span>b – 2a – c
= 9 - 2(-3) - (-6)
= 9 + 6 + 6
= 21

answer
21</span>

3 0

3 years ago

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