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Answer:
Given : The sample mean score is 51.48 .
The standard deviation for the population of test scores is 15.
The nationwide average score on this test is 50.
To Find : Perform the hypothesis test and compute the P-value?
Solution:
Sample size = n = 64
Since n > 30
So, we will use z test over here
We are supposed to find The school superintendent wants to know whether the second-graders in her school district have greater math skills than the nationwide average.
Hypothesis :
Formula of z test :
Substitute the values
Find the value of P(z) from z table
p(z)=0.7823
Since we are given that we are supposed to find The school superintendent wants to know whether the second-graders in her school district have greater math skills than the nationwide average.
So, p value = 1-P(z) = 1-0.7823=0.2177
In general , Level of significance is 0.05
So, p value is greater than alpha.
So, we accept the null hypothesis.
Answer:
a. 8.66 minutes
Step-by-step explanation:
Since the flight times are uniformly distributed, the standard deviation can be calculated as follows:
Where '<em>b' </em>is the maximum flight time (150 minutes) and '<em>a' </em>is the minimum flight time (120 minutes):
The distribution's standard deviation is 8.66 minutes.
Answer:
A 99% confidence interval will be wider than a 95% confidence interval
Step-by-step explanation:
From the question we are told that
The 95% confidence interval for for the mean foot length for students at the college is found to be 21.709 to 25.091 cm
Generally the width of a confidence interval is dependent on the margin of error.
Generally the margin of error is mathematically represented as
From the above equation we see that
Here is the critical value of the half of the level of significance and this value increase as the confidence level increase
Now if a 99% confidence level is used , it then means that the value of
will increase, this in turn will increase the margin of error and in turn this will increase the width of the confidence interval
Hence a 99% confidence interval will be wider than a 95% confidence interval