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3 years ago

What are some of the applications for exponential functions

2 answers:

7 0

Exponential functions help us in reducing higher dimensional equivalents into smaller ones , simply , we have an advantage over using exponents , indices , simultaneously ,

we can substitute x² = t in any equation which has raised to the power 4 , it'll result in t² for sure ,

SO , the above illustration is the most basic and common application of exponential functions , rest is utilized in reducing logarithmic , trigonometric functions and so on more

scoundrel [369]3 years ago

3 0

Answer:

The special matter about exponential functions is that they can be very beneficial in day to day situations.

Exponential functions are beneficial to carbon date artifacts, compute investments, help coroners determine the death time, model populations as well as many other applications.

Three of the very common applications for exponential functions:

population growth
exponential decay
compound interest.

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Lengths of full-term babies in the US are Normally distributed with a mean length of 20.5 inches and a standard deviation of 0.9

mash [69]

Answer:

66.48% of full-term babies are between 19 and 21 inches long at birth

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean length of 20.5 inches and a standard deviation of 0.90 inches.

This means that $\mu = 20.5, \sigma = 0.9$

What percentage of full-term babies are between 19 and 21 inches long at birth?

The proportion is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19. Then

X = 21

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{21 - 20.5}{0.9}$

$Z = 0.56$

$Z = 0.56$ has a p-value of 0.7123

X = 19

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{19 - 20.5}{0.9}$

$Z = -1.67$

$Z = -1.67$ has a p-value of 0.0475

0.7123 - 0.0475 = 0.6648

0.6648*100% = 66.48%

66.48% of full-term babies are between 19 and 21 inches long at birth

5 0

2 years ago

The area of square LMNO is 130 square inches. Find the length of Segment LM.

lakkis [162]

Answer:

11.401754251 or the square root of 130

Step-by-step explanation:

the length squared is the area so you have to do inverse operations and do the square root

4 0

3 years ago

2x + 3 = 4x^2<br> completing the square

ch4aika [34]

Answer:

$\frac{1+\sqrt{13} }{4}, \frac{1-\sqrt{13} }{4}$

Step-by-step explanation:

First, make them on one side of the formula in the form of $ax^2+bx+c=0$ which is $4x^{2} -2x-3=0$

Next, insert the corresponding number in the quadratic formula, $\frac{-b+\sqrt{b^{2}-4ac } }{2a} ,\frac{-b-\sqrt{b^{2}-4ac } }{2a}$ , and the answer can be calculated.