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Elis [28]
3 years ago
12

Please Help!

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

See attached

Step-by-step explanation:

<em>Refer to attachment</em>

  • a. Law of Syllogism
  • b. No valid conclusion
  • c. Law of Detachment

vichka [17]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

a.  Law of syllogism,  the statement is not true.

b.  No valid conclusion

c.  Law of detachment, the statement or conclusion is true.

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Exhibit 18-2 Students in statistics classes were asked whether they preferred a 10-minute break or to get out of class 10 minute
tankabanditka [31]

Answer:

The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82

Step-by-step explanation:

According to the given data we have the following:

Total sample of students= 150

80 students preferred to get out 10 minutes early

Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533

Therefore,  standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)

= 0.533-0.5/sqrt(0.5*0.5/15))

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3 0
3 years ago
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babunello [35]

Answer:

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6 0
2 years ago
Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

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Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

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P (X ≥ 280) = P (X > 280 + 0.50)

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*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

8 0
3 years ago
A 150 pound woman would recieve 24 grams of a certain medicine. How many grams should a 120 pound woman receive?​
eduard

Answer:

This is matter of ratio!

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Please Mark Brainliest!!

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3 years ago
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