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Elis [28]
3 years ago
12

Please Help!

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0

Answer:

See attached

Step-by-step explanation:

<em>Refer to attachment</em>

  • a. Law of Syllogism
  • b. No valid conclusion
  • c. Law of Detachment

vichka [17]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

a.  Law of syllogism,  the statement is not true.

b.  No valid conclusion

c.  Law of detachment, the statement or conclusion is true.

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PLZ HELP ASAP!!
Lilit [14]

The measure of first angle is 34 degrees and measure of second angle is 56 degrees

<em><u>Solution:</u></em>

Given that, the exterior sides of two adjacent angles make a right angle

Therefore, these adjacent angles forms 90 degrees

Let the second angle be "x"

The first angle has a measure that is six more than half the second

Therefore,

first angle = 6 + half of "x"

\text{ first angle } = 6 + \frac{x}{2}

Since these two angles forms 90 degrees,

first angle + second angle = 90

x + 6 + \frac{x}{2} = 90\\\\\frac{2x + 12 + x}{2} = 90\\\\2x + 12+x = 180\\\\3x + 12 = 180\\\\3x = 180 - 12\\\\3x = 168\\\\x = 56

<em><u>Therefore, first angle is:</u></em>

\rightarrow 6 + \frac{56}{2} = 6 + 28 = 34

Thus measure of first angle is 34 degrees and measure of second angle is 56 degrees

6 0
3 years ago
Find all the complex roots. Write the answer in exponential form.
dezoksy [38]

We have to calculate the fourth roots of this complex number:

z=9+9\sqrt[]{3}i

We start by writing this number in exponential form:

\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}

Then, the exponential form is:

z=18e^{\frac{\pi}{3}i}

The formula for the roots of a complex number can be written (in polar form) as:

z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})

We can now calculate for each value of k:

\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0
1 year ago
WILL GIVE BRAIINLIEST ANSWER Tomas is at least 7 years older than Larry. If Tomas is 16 years old, how old is Larry?
ra1l [238]
Larry - ( 9 years old )
8 0
3 years ago
For questions 1 – 6, find the area of the circle to the nearest hundredth.<br> Any help appriciated!
Ganezh [65]

Step-by-step explanation:

The area of a circle is given by :

A = πr²

r is the radius of the circle

(4) Diameter = 22 cm

Since, radius = diameter/2

r = 11 cm

Now, area of the circle,

A=\pi \times (11)^2\\\\A=380.13\ cm^2

(5) Diameter = 30 cm

Since, radius = diameter/2

r = 15 cm

Now, area of the circle,

A=\pi \times (15)^2\\\\A=706.85\ cm^2

(6) Diameter = 4cm

Since, radius = diameter/2

r = 2 cm

Now, area of the circle,

A=\pi \times (2)^2\\\\A=12.56\ cm^2

So, the area of circles 4,5 and 6 are 380.13², 706.85² and 12.56² respectively.

4 0
3 years ago
Ohhhh please help me I have a really bad grade in math
-Dominant- [34]

1) C 2) B I hope this helps!

4 0
3 years ago
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