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netineya [11]
3 years ago
15

There are 2 black balls, one red ball and one green ball, identical in shape and size. How many different linear arrangements ca

n be generated by arranging these balls?
Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer: The number of different linear arrangements can be generated by arranging these balls is 12.

Step-by-step explanation:

The number of ways to arrange n things in a line where a things are like and b  things are like is \dfrac{n!}{a!\ b!\ ....}

Given : There are 2 black balls, one red ball and one green ball, identical in shape and size.

Total balls = 2+1+1=4

Here 2 black balls are alike.

So , the number of different linear arrangements can be generated by arranging these balls would be\dfrac{4!}{2!}=\dfrac{4\times3\times2!}{2!}=12

Hence, the number of different linear arrangements can be generated by arranging these balls is 12.

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Order from greatest to least.<br> 0.386,0.3,0.683,0.836
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