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netineya [11]
3 years ago
15

There are 2 black balls, one red ball and one green ball, identical in shape and size. How many different linear arrangements ca

n be generated by arranging these balls?
Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer: The number of different linear arrangements can be generated by arranging these balls is 12.

Step-by-step explanation:

The number of ways to arrange n things in a line where a things are like and b  things are like is \dfrac{n!}{a!\ b!\ ....}

Given : There are 2 black balls, one red ball and one green ball, identical in shape and size.

Total balls = 2+1+1=4

Here 2 black balls are alike.

So , the number of different linear arrangements can be generated by arranging these balls would be\dfrac{4!}{2!}=\dfrac{4\times3\times2!}{2!}=12

Hence, the number of different linear arrangements can be generated by arranging these balls is 12.

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$3.00 / 6.5 oz = [unknown $] / 104 oz

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Answer:

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Step-by-step explanation:

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To check for our answer, we can simply substitute the values including the principal and excluding the total.

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