How many 12 inch rulers would be the same length as a door

Can someone help me with this question please..

lord [1]

Answer:

(0,3)

Step-by-step explanation:

Find the point D and then read the value off of the x axis (horizontal) first and then the y axis (vertical).

3 0

3 years ago

LINEAR EQUATIONS PLZ HELP BRAINLIEST AND EXTRA POINTS!!!

Oliga [24]

Answer:

1) B) a = 14

2)D) x = -11

3)B) x = 8

4)A) 250 = 3c-20

5)D)8

6)B), C), D)

8)A) 14 months

9)Sarah = 40 years

Sarah = 5/4 x Tanya

40 = 5/4 x Tanya's age

Therefore Tanya's age is 32 years old

Hope this helps you!

4 0

3 years ago

Read 2 more answers

last year a state university received 3,560 application from boys of those application 35% were boys who lived in other states h

LuckyWell [14K]

3560 * 35/100
3560 * 0.35
= 1246 students lived in other states

4 0

3 years ago

At one point the average price of regular unleaded gasoline was $3.41 per gallon. Assume that the standard deviation price per

Aleonysh [2.5K]

Answer:

a) $1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

b) $1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

c) We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

Step-by-step explanation:

Previous concepts and Data given

$\mu =3.41$ reprsent the population mean

$\sigma=0.09$ represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: $1-\frac{1}{k^2}$

Part a

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75$

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

$1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556$

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

$Lower = 3.41 -1.5*0.09 = 3.275$

$Upper = 3.41 +1.5*0.09 = 3.545$

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

$z =\frac{x-\mu}{\sigma}$

And using the lower limit we got:

$z = \frac{3.05-3.41}{0.09}=-4$

And with the upper limit we got:

$z = \frac{3.77-3.41}{0.09}=4$

So then the value of k =4 and the percentage is given by:

$1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375$

3 0

3 years ago

Customers at a candy store took a survey. The results showed that 126 customers preferred chocolate candy. This represented 35%

zepelin [54]

Answer:

360

Step-by-step explanation:

1. Set up your equation!

$\frac{35}{100}$ = $\frac{126}{x}$

2. Cross multiply to solve!

100 times 126 = 12600

35 times x = 36x

3. Continue!

12600=35x

4. Divide the coefficient on both sides to get the variable by itself

$\frac{12600}{35}$ =x (the 35 cancels out)

12600 divided by 35 = 360

And there’s your answer! 360

5 0

2 years ago