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maw [93]
2 years ago
14

Pls help. due at 11:59

Mathematics
1 answer:
Nadusha1986 [10]2 years ago
6 0

Answer:

see the attachment!

i hope this can help you.

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Victor needs to box 61 laptop computers for a shipment. If he can fit 9 laptops in each box, how many boxes does he need?
just olya [345]

Answer:

he would need 7 boxes

Step-by-step explanation:

61/9= 6 with a remainder of 7 therefore instead of 6 boxes you would need 7 to put the rest of the laptops in

7 0
4 years ago
Hi how are you? :)<br><br> free points &lt;3
bixtya [17]

Answer:

thank you

Step-by-step explanation:

can I get brainiest please

7 0
3 years ago
Read 2 more answers
Determine the area under the standard normal curve that lies to the right of the z-score 0.48 and to the left of the z-score 0.7
pychu [463]

Answer:

The area lies to the right of the z-score 0.48 means all the values greater than it. This can be calculated on a graphing calculator using the function normCdf, where

  • Lower bound = 0.48
  • Upper bound = 9999
  • Mean = 0
  • Standard deviation = 1

<u>The result would be normCdf(0.48,9999,0,1) ≈ </u><u>0.315614</u>

<u />

The area lies to the left of the z-score 0.79 means all the values less than it. This can be calculated on a graphing calculator using the function normCdf, where

  • Lower bound = -9999
  • Upper bound = 0.79
  • Mean = 0
  • Standard deviation = 1

<u>The result would be normCdf(-9999,0.79,0,1) ≈</u><u> 0.785236</u>

6 0
3 years ago
Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

8 0
4 years ago
I need the anwser and the fractions
alexandr1967 [171]

Answer:

5.5/3 - 3/1 = 2.5/3

7 0
3 years ago
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