Question

Dan had $34 to spend at the fair if the admission to the fair is $10 and the rides cost $1.50 each, what is the greatest number of rides dan can go on. write an inequality that represents dan's situation

Answer 1

Answer:

Equation: 1.50x + 10 $\leq$ 34

Amount of rides Dan can go on: 16 rides

Step-by-step explanation:

We can represent this situation using this equation:

1.50x + 10 $\leq$ 34

The $10 Dan has to pay as admission is the fixed number because it doesn't vary and always remains the same, so no x goes next to 10.

Each ride costs $1.50 so this is the variable number as it changes with how many rides Dan goes on, therefore an x will go next to 1.50 to represent the amount of rides Dan goes on.

Lastly, Dan has $34 to spare, so the amount spent has to be less than or equal 34.

Solve the equation for x to find the greatest amount of rides Dan can go on:

1.50x + 10 $\leq$ 34                      Subtract 10 from 34

1.50x $\leq$ 24                             Divide 24 by 1.50

x $\leq$ 16

So, Dan has enough money to go on 16 rides or less.

Let's check this answer:

1.50(16) + 10 $\leq$ 34                   Multiply 1.50 by 16

24 + 10 $\leq$ 34                           Add 24 and 10

34 $\leq$ 34

Hope this helps! Good luck and if you have any questions let me know in the comments!