2(s+3)=4s-5
2s+6=4s-5
4s-2s=5+6
2s=11
s=5,5
Answer:
s for length of either equal side
b for the unequal side
b=-2+2*(s+s) and 2s+b=40
b=2*2s-2
b=4s-2
2s+4s-2=40
6s-2=40
6s=42
s=7
b=4*7-2
b=28-2
b=26
First step is to distribute.
-4a^2 - 6a +2 + 3a^2 -3
Combine like terms
-a^2 -6a -1
the problem would be set up as 6+(7*x)=41
first u take off the number 6 by subtracting it from itself to cancel it out then u do the same to the number 41
7x =41 now u need to cancel out the number 7 attatched to the x so u divikde it by itself and then do the same to the other side so 41 divided by 7 =5.9
so x =5.9
