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Juliette [100K]
1 year ago
12

Find the value of Y.

Mathematics
2 answers:
Lana71 [14]1 year ago
8 0

Angle 60

Opposite - y

Hypotenuse - 10

OH - SOH

Sin60 = o/h

Sin60 = o/10

x10

O = sin60 x 10

O = 5 root 3

= 8.660254....

So, value of y = 8.66 to 2d.p

Hope this helps!

Deffense [45]1 year ago
7 0

Answer:

  5√3

Step-by-step explanation:

The ratio of side lengths in a 30-60-90 triangle is ...

  1 : √3 : 2

__

Multiplying by 5, we have ...

  1 : √3 : 2 = x : y : 10 = 5 : 5√3 : 10

The value of y is 5√3.

_____

<em>Additional comment</em>

y is the side adjacent to the 30° angle, so can be found from ...

  Cos = Adjacent/Hypotenuse

  Adjacent = Cos × Hypotenuse . . . . . multiply by hypotenuse

  y = cos(30°)×10 = (√3)/2 × 10 . . . . . . substitute corresponding values

  y = 5√3

__

The value of x is 5.

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Christopher buys 120 hot dog buns for a picnic. He buys two different brands of hot dog buns. Brand X has 12 hot dog buns in a p
lianna [129]

A system of equations that can be used to find the number of packages of Brand X hot dog buns and Brand Y hot dog buns that Christopher buys is:

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4.5x + 3.5y = 49.50.

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The following equations can be derived from the question

12x + 8y = 120  equation 1

4.5x + 3.5y = 49.50 equation 2

x represents the number of packages of Brand X

y represents the number of packages of Brand Y

The elimination method would be used to determine the values of x and y

Multiply equation 1 by 4.5 and equation 2 by 12

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Substitute for y in equation 1

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6 0
3 years ago
Explain why each statement is true. 5 + 2 + 3 = 5 + (2 + 3)
Y_Kistochka [10]

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Associative property of addition. Grouping different addends does not change the sum.

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(1 point) (a) Find the point Q that is a distance 0.1 from the point P=(6,6) in the direction of v=⟨−1,1⟩. Give five decimal pla
natima [27]

Answer:

following are the solution to the given points:

Step-by-step explanation:

In point a:

\vec{v} = -\vec{1 i} +\vec{1j}\\\\|\vec{v}| = \sqrt{-1^2+1^2}

    =\sqrt{1+1}\\\\=\sqrt{2}

calculating unit vector:

\frac{\vec{v}}{|\vec{v}|} = \frac{-1i+1j}{\sqrt{2}}

the point Q is at a distance h from P(6,6) Here, h=0.1  

a=-6+O.1 \times \frac{-1}{\sqrt{2}}\\\\= 5.92928 \\\\b= 6+O.1 \times \frac{-1}{\sqrt{2}} \\\\= 6.07071

the value of Q= (5.92928 ,6.07071  )

In point b:

Calculating the directional derivative of f (x, y) = \sqrt{x+3y} at P in the direction of \vec{v}

f_{PQ} (P) =\fracx{f(Q)-f(P)}{h}\\\\

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In point C:

Computing the directional derivative using the partial derivatives of f.

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