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3 years ago

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Mathematics

1 answer:

rjkz [21]3 years ago

8 0

Answer:

I think it might be D

Step-by-step explanation:

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Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio. She sold a th

Licemer1 [7]

Given :

Rema purchased 18 ounces of gold in 2005 for $414 per ounce in order to try to diversify her investment portfolio.

She sold a third of her holdings in gold in 2009 at a price $953 per ounce. She sold the rest of her gold holdings in 2010 for $1,367 per ounce.

To Find :

What is Prema’s profit in 2009 and 2010.

Solution :

Price of one third ounces of gold, in 2005 is :

P = $414/3 = $138 .

Profit from selling them in 2009 is :

P1 = $(953 - 138) = $815 .

Profit from selling them in 2010 is :

P2 = $( 1367 - ( 414 - 138 ) ) = $1091 .

Therefore, Prema's profit in 2009 is $815 and 2010 is $1091.

Hence, this is the required solution.

5 0

3 years ago

The amount in kilograms, a, of a radioactive element that remains after t hours can be modeled by the equation a= 0.65(0.92)to t

elena-14-01-66 [18.8K]

Answer:

The rate of decrease is 8%

Step-by-step explanation:

we know that

The general equation for the radioactive decay can be written as:

$a=a_0(1-r)^t$

where

a is the amount in kilograms after time t.

a_0 is the original amount of the substance or y-intercept of the function

r is the decay rate, written in decimals.

t is the time

In this problem we have

$a=0.65(0.92)^t$

$a_0=0.65\\(1-r)=0.92$

solve for r

$r=1-0.92=0.08$

Convert to percentage

$0.08(100)=8\%$

6 0

4 years ago

PLEASE HELP ME ASAP ?!?!?

GaryK [48]

Answer:

m = 5 n = $\frac{5\sqrt{3} }{2}$

Step-by-step explanation:

5/2x2=5

5/3xsqrt3=5sqrt3/2

3 0

3 years ago

Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the

beks73 [17]

In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: $m= \frac{P( \frac{r}{12}) }{1-(1+ \frac{r}{12})^{-12t} }$
where
$m$ is the monthly payment
$P$ is the amount
$r$ is the interest rate in decimal form
$t$ is the number years

First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
$\frac{4}{100} =0.04$
We also know from our question that $P=224500$ and $t=30$ , so lets replace those values into our formula to find the monthly payment:
$m= \frac{224500( \frac{0.04}{12}) }{1-(1+ \frac{0.04}{12})^{-(12)(30)} }$
$m=1071.80$

We can conclude that the monthly payment during the initial period is $1071.58

7 0

3 years ago

|f−6|=|f+8| please help

soldi70 [24.7K]

Answer:f=-1

Step-by-step explanation:

6 0

4 years ago