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2 years ago

Which one does not belong8 27 64 16

Mathematics

1 answer:

Brums [2.3K]2 years ago

7 0

Answer:

27 doesn't belongs to this group

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A robot can complete 7 tasks in

SSSSS [86.1K]

Answer:

5/42 is your answer take robot to complete

7 tasks = 5/6

1 task = 5/42 hour.

1 hour / (5/42 hour/task) = 15/2 tasks = 8.2 tasks.

half a task isn’t a complete task, so the answer is 8 tasks.

5 0

2 years ago

What are the solutions to the systems? y=x^2-4x-2 y=x-2

kirill115 [55]

y=x^2-4x-2
y=x-2

$x^2-4x-2=x-2\\\\x^2-4x-2-x+2=0\\\\x^2-5x=0\\\\x(x-5)=0\\\\x=0 \ or \ x-5=0$

x=0 or x=5

y = x - 2
1)
x=0
y = 0 - 2= -2
2)
x=5
y=5-2=3

Answer
x=0 , y=-2
or
x=5 , y=3

6 0

2 years ago

Which number line shows the solution to 11x + 14 <-8

kkurt [141]

Answer:

The answer is D

Step-by-step explanation:

I did it on edg

8 0

2 years ago

Remember to show work and explain. Use the math font.

MrMuchimi

Answer:

$\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}$

Step-by-step explanation:

$\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================$

$1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}$

$\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)$

$--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)$

$--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}$

6 0

3 years ago

Are these expressions equivalent 3(5b-2) and 8b-5

Pavel [41]

No, if you multiply the factors in 3(5b-2) the equivalent expression would be 15b-6

4 0

2 years ago

Read 2 more answers

Which one does not belong8 27 64 16​

Which one does not belong8 27 64 16