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2 years ago

14

Find the value of sin E rounded to the nearest hundredth, if necessary.

1 answer:

Oduvanchick [21]2 years ago

6 0

Answer:

Step-by-step explanation:

using sin formula

$\frac{sin~E}{15} =\frac{sin ~90}{39} \\sin ~E=15 \times ~\frac{1}{39} =\frac{5}{13}$

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5^11 times 5^3 = 5^?

postnew [5]

Answer:

$5^{13}$

Step-by-step explanation:

$5^{11}\times \:5^2$

<u>Apply exponent rule : </u> $a^b\times \:a^c=a^{b+c}$

$5^{11}\times \:5^2=5^{11+2}$

$5^{11+2}$

<u>Add 11 +2 = 13</u>

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7 0

2 years ago

x= infinity; 9x to the power of 3 + x to the power of 2 - 5 divided by 3x to the power of 4 + 4x to the power of 2

Delvig [45]

Answer:

here n Hope it helps. goodluck

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1 year ago

Can someone tell me… Given the right triangle ABC, what is the value of tan(A)?

sergey [27]

Answer:

C

Step-by-step explanation:

tanA = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{24}{10}$ = $\frac{12}{5}$ → C

6 0

2 years ago

In a class of 50 students, everyone has either a pierced nose or a pierced ear. The professor asks everyone with a pierced nose

Tems11 [23]

Answer: 3

Step-by-step explanation:

Let E be the event of that student pierces ear and N be the event of that student pierces nose.

Given: $n(E\cup N=50)$

$n(E)=46\\\\n(N)=7$

For any two event A and B, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

Similarly , $n(E\cup N)=n(E)+n(N)-n(E\cap N)$

$50=46+7-n(E\cap N)\\\\\Rightarrow\ n(E\cap N)=53-50=3$

Hence, 3 students have piercings both on their ears and their noses.

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2 years ago

What are the solutions to the equation 3x2 + 15x = 18?

jok3333 [9.3K]

$3x {}^{2} + 15x = 18$

<h2>Divide the entire thing by 3</h2>

$x {}^{2} + 5x = 6$

$x {}^{2} + 5x - 6 = 0$

<h2>You can find the roots by using the quadratic formula or by using the form x²-Sx+P</h2>

$let \: \alpha \: and \: \beta \: be \: the \: roots$

<h2>Two numbers whose sum is -5 and product is -6</h2><h2>-6 and +1</h2>

<h2>Your answer is B</h2>

6 0

1 year ago