Calculate 7 1/4 tax on $1,540. a. $11.17 b. $109.34 c. $111.65 d. $113.96
2 answers:
The question is asking us to find tax on an amount of $1,540 at the rate of Percent means out of 100.
7.25% =0.0725.
To find the tax to be paid we need to find 0.0725 of 1,540.
Tax to be paid = 0.0725x1540=111.65.
Tax on amount of $1540 at the rate of tex]7\frac{1}{4}%[/tex] is $111.65.
Option c. $111.65 is the right answer.
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The given function are
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>
<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>
As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>
r(x) = 2 - x² and w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
= 2x - x³ - 4 + 2x²
∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>
<span>It is a polynomial function with a domain equal to R
</span>
The range of <span>(w*r)(x) can be obtained by graphing the function
</span>
To graph (w*r)(x), we need to make a table between x and (w*r)(x)
See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>
As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
</span>
Answer:
a) , n = 15 , X=3.4 , S=1.5 , α = .05
Formula :
p- value = 0.607(using calculator)
α = .05
p- value > α
So, we failed to reject null hypothesis
b) , n =75 , X=20.12 , S=2.1 , α = .10
Formula :
p- value = 0.000412(using calculator)
α = .1
p- value< α
So, we reject null hypothesis
(c) , n = 36, p-value = 0.061.
Assume α = .05
p-value = 0.061.
p- value > α
So, we failed to reject null hypothesis