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2 years ago

13

Regress smoker on quadratic polynomials of age, using a probit regression and find the p-value for testing the hypothesis that t

he z-value is linear in age. (two decimal places)

1 answer:

defon2 years ago

6 0

The answer is “40 years old individuals would smoke with the probability do, so with the probability of 24.22%”

<h3>What is probit regression?</h3>

A probit model is a type of regression in statistics where the dependant variable can only take two values.

We have:

Regress smoker on quadratic polynomials of age.

If we use probit regression.

The statement 40 years old individuals would smoke with the probability do, so with the probability of 24.22% is wrong about the statement.

Thus, the answer is “40 years old individuals would smoke with the probability do, so with the probability of 24.22%”

Learn more about the probit regression here:

brainly.com/question/23389011

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Transparency and worksheet master lesson 4.2 page 166

arlik [135]

Http://mrdealy.weebly.com/uploads/2/3/5/2/23520438/geom._ch._3_angle_diagrams__3.8_worksheet.pdf

3 0

3 years ago

What is the x-coordinate of the solution of the system?<br> x+y+3<br> 4x-y=-38

steposvetlana [31]

<em>Note: I am assuming the first equation is:</em>

<em>x+y = 3</em>

Answer:

The solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x+y=34\\ x-y=-38\end{bmatrix}$

subtracting the equations

$x-y=-38$

$-$

$\underline{x+y=34}$

$-2y=-72$

solve -2y for y

$-2y=-72$

Divide both sides by -2

$\frac{-2y}{-2}=\frac{-72}{-2}$

$y=36$

For x+y=34 plug in y = 36

$x+36=34$

Subtract 36 from both sides

$x+36-36=34-36$

Simplify

$x=-2$

Thus, the solution to the system of equations is:

(x, y) = (-2, 36)

Therefore, the x-coordinate of the solution of the system

x = -2

6 0

3 years ago

The sum of three numbers is 84 the second number is 3 times the third . The first number is 6 less then the third . What are the

Kamila [148]

Answer:

A=12

B=54

C=18

Step-by-step explanation:

A=first

B=second

C=third

A+B+C=84

B=3C

A=C-6

C-6+3C+C=84

5C-6=84

5C=90

C=18

A=C-6

=(18)-6

=12

B=3C

=3(18)

=54

7 0

4 years ago

Whats the Answer? (i saw someone post this but with no picture i hope this can help)

amid [387]

The answer is the letter C. 96

8 0

3 years ago

Read 2 more answers

Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17

V125BC [204]

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

$\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}$

Cramer's rule says that

$x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}$

where $x_i$ is the solution for i-th variable, and $\mathbf A_i$ is a modified version of $\mathbf A$ with its i-th column replaced by $\mathbf b$ .

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

$\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}$

$\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}$

$\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))$

$\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120$

The modified matrices and their determinants are

$\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240$

$\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360$

$\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480$

Then by Cramer's rule, the solution to the system is

$x = \dfrac{-240}{-120} \implies \boxed{x = 2}$

$y = \dfrac{360}{-120} \implies \boxed{y = -3}$

$z = \dfrac{-480}{-120} \implies \boxed{z = 4}$

5 0

2 years ago