For a
0 > -3(1) + 3 i.e. 0 > 0 (not true)
For b
1 > -3(-1) + 3 i.e. 1 > 6 (not true)
For c
2 > -3(2) + 3 i.e. 2 > -3 (true)
2 > 2(2) - 2 i.e. 2 > 2 (not true)
For d
3 > -3(0) + 3 i.e. 3 > 3 (not true)
Therefore, none of the ordered pairs makes both inequalities correct.
Answer:
x≤-2
Step-by-step explanation:
it would be that because if the graph is going to the left that means it is less than x and the opposite is for greater than. Now if there is a closed circle that means the sign is equal to hence the line under the sign. So therefore it's x≤-2
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
wait i think i did the wrong one brb
Answer:
CoCl2*6H2O = CoCl2 + 6 H2O
Step-by-step explanation:
Reaction type is decomposition, but this should balance it.
