Question

PLEASE HELP!?!?

Answer 1

The table has been filled out in the attachment given in the answer

1. These are the values to fill out the table

We have A(d) = $150.k^d$

k = √1/2

$A(d) = 150*\frac{1}{2} ^d^/^2$

How to substitute the values into the equation

When d = 1

$A(d) = 150*\frac{1}{2} ^1^/^2$

A(d) = 75√2

= 106.1

When A(d) = 3

$\frac{75\sqrt{2} }{2} = 53$

When we substitute the value of A(d) = 4

= 37.5

2.  B(D) = 100 * 2^-D / 7

$2^-^1^/^2 < 2^-^1^/^7$

The two algae blooms that is larger initially is A(D) Also the one that is increasing more quickly is also A(D).

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