Answer:
See explaination
Explanation:
#include <stdio.h>
#include <stdlib.h>
int main()
{
FILE * file_object;
char file_name[100];
char ch;
int characters=0, words=0;
printf("Enter source file name: ");
scanf("%s", file_name); //asking user to enter the file name
file_object = fopen(file_name, "r"); //open file in read mode
if (file_object == NULL)
{
printf("\nUnable to open file.file not exist\n"); //check if the file is present or not
}
while ((ch = fgetc(file_object)) != EOF) //read each character till the end of the file
{
if (ch == ' ' || ch == '\t' || ch == '\n' || ch == '\0') //if character is space or tab or new line or null character increment word count
words++;
else
characters++; //else increment character count this assures that there is no spaces count
}
printf("The file story.txt has the following Statistics:\n"); //finally print the final statistics
if (characters > 0)
{
printf("Words: %d\n", words+1); //for last word purpose just increment the count of words
printf("Characters (no spaces): %d\n", characters);
}
fclose(file_object); //close the file object
return 0;
}
Answer:
The sum of all positive even values in arr
Explanation:
We have an array named arr holding int values
Inside the method mystery:
Two variables s1 and s2 are initialized as 0
A for loop is created iterating through the arr array. Inside the loop:
num is set to the ith position of the arr (num will hold the each value in arr)
Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).
When the loop is done, the value of s1 and s2 is printed.
As you can see, s1 holds the sum of positive even values in the arr
I will hope this helps :p
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I hope you can understand this and it helps!!
