Microsoft words spell checker

Declare an array named a of 10 elements of type int and initialize the elements (starting with the first) to the values 10, 20,

kherson [118]

Answer:

int a[10] = {10,20,30,40,50,60,70,80,90,100};

Explanation:

In the above statement, we declare the integer data type array variable that is 'a' then, pass its index value that is 10 which means it contains only 10 values and initialize the components of the array variable that is starting with 10 and end at 100 in the difference of 10. So, the following declaration is correct according to the statement.

5 0

3 years ago

Which is an acceptable practice when a photographer shoots in windy conditions?

VARVARA [1.3K]

Answer:

d) attach a bag of weights to the tripod

Explanation:

5 0

3 years ago

Which protocol below is used to email clients to send email

AVprozaik [17]

The Internet Message Access Protocol (IMAP) is a mail protocol used for accessing email on a remote web server from a local client. IMAP and POP3 are the two most commonly used Internet mail protocols for retrieving emails

4 0

3 years ago

Write a program in Java programming language that given two clock times prints out the absolute number of minutes between them

Triss [41]

Answer:

// Java Program to Find the difference

// between Two Time Periods

// Importing the Date Class from the util package

import java.util.*;

// Importing the SimpleDateFormat

// Class from the text package

import java.text.*;

public class GFG {

public static void main(String[] args) throws Exception

{

// Dates to be parsed

String time1 = "18:00:00";

String time2 = "7:30:50";

// Creating a SimpleDateFormat object

// to parse time in the format HH:MM:SS

SimpleDateFormat simpleDateFormat

= new SimpleDateFormat("HH:mm:ss");

// Parsing the Time Period

Date date1 = simpleDateFormat.parse(time1);

Date date2 = simpleDateFormat.parse(time2);

// Calculating the difference in milliseconds

long differenceInMilliSeconds

= Math.abs(date2.getTime() - date1.getTime());

// Calculating the difference in Hours

long differenceInHours

= (differenceInMilliSeconds / (60 * 60 * 1000))

% 24;

// Calculating the difference in Minutes

long differenceInMinutes

= (differenceInMilliSeconds / (60 * 1000)) % 60;

// Calculating the difference in Seconds

long differenceInSeconds

= (differenceInMilliSeconds / 1000) % 60;

// Printing the answer

System.out.println(

"Difference is " + differenceInHours + " hours "

+ differenceInMinutes + " minutes "

+ differenceInSeconds + " Seconds. ");

}

7 0

2 years ago

Write a program that would determine the day number in a non-leap year. For example, in a non-leap year, the day number for Dec

SOVA2 [1]

Answer:

In Python:

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

day = int(input("Day: "))

month = input("Month: ")

ind = months.index(month)

numday = 0

for i in range(ind):

numday+=daymonths[i]

numday+=day

print(numday)

Explanation:

This initializes the months to a list

months = ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"]

This initializes the corresponding days of each month to a list

daymonths = [31,28,31,30,31,30,31,31,30,31,30,31]

This gets the day from the user

day = int(input("Day: "))

This gets the month from the user

month = input("Month: ")

This gets the index of the month entered by the user

ind = months.index(month)

This initializes the sum of days to 0

numday = 0

This adds up the days of the months before the month entered by the user

for i in range(ind):

numday+=daymonths[i]

This adds the day number to the sum of the months

numday+=day

This prints the required number of days

print(numday)

Note that: Error checking is not done in this program

7 0

3 years ago