∫( (sinx) / (2 - 3cosx)) dx.
From laws of integration: ∫ f¹(u) / f(u) du = In(f(u)) + constant.
d/dx (2 - 3cosx) = 0 -3(-sinx) = 3sinx.
1/3d/dx(2 - 3cosx) = (1/3)*3sinx = sinx.
∫ ((sinx) / (2 - 3cosx)) dx. = ∫ ((1/3) d/dx (2 - 3cosx) / (2 - 3cosx))dx
= 1/3 ∫ (d/dx (2 - 3cosx) / (2 - 3cosx))dx
= (1/3)ln(2 - 3cosx) + Constant.
Answer:
2/5 or 40%
Step-by-step explanation:
total students=30
female students=18
That must mean, assuming the rest of the class is binary male=12
12/30=2/5 or 40% if you multiply by 20, then multiply by 100%
(2/5)*20=.40*100%=40%
Answer:
measure of other diagonal is 30cm
Step-by-step explanation:
let the other diagonal be d .
- area of rhombus = 1/2 × 16 × d
- 240 = 8 × d
- d = 240 / 8
- d = 30
hence the other diagonal = d = 30 cm
Answer:
no question
Step-by-step explanation:
prove what?
