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yaroslaw [1]
2 years ago
6

7men have 7wives, each man and each wife have 7children what is total number of people​

Mathematics
1 answer:
UkoKoshka [18]2 years ago
7 0

Answer:

63

Step-by-step explanation:

If 7 men have 7 wives, that means they have 1 wife each, so that will be 7+7=14. Then each wife has 7 children, so that will be 7×7=49, next we add the children to the men and the wives and get 49+14=63. So the total number of people is 63.

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Quadrilateral ABCD is inscribed in a circle. Angle B measures 19°. What is the measure of angle D?
kherson [118]

Answer:

D = 161^o

Step-by-step explanation:

Given

\angle B = 19^o

Required

Find D

The label of the quadrilateral are not clear. However, a more complete question illustrates that B and D are opposite sides.

To solve for D, we make use of:

B + D = 180^o ---- opposite sides of a cyclic \\ quadrilateral

Make D the subject

D = 180^o -B

D = 180^o -19^o

D = 161^o

5 0
3 years ago
A brownie recipe asks for tow and one third times as much sugar as chocolate chips. If three and one half cups of sugar is used,
sladkih [1.3K]
Abdhajajsjehehsusuwh nini are good djalma he ysiwjegdve
8 0
3 years ago
Find the probability that when a couple has three children, at least one of themis a girl. (Assume that boys and girls are equal
kvv77 [185]

Answer:   \bold{\dfrac{7}{8}=87.5\%}

<u>Step-by-step explanation:</u>

"At least one girl" means P(1 girl) + P(2 girls) + P(3 girls)   or   1 - P(all boys)

I will use the latter: 1 - P(all boys)

P(all boys) = \dfrac{1}{2}\times \dfrac{1}{2}\times \dfrac{1}{2}=\dfrac{1}{8}

1 - P(all\ boys) \quad = \quad 1-\dfrac{1}{8}\quad =\large\boxed{\dfrac{7}{8}}

6 0
3 years ago
11+m&gt;15 what’s the answer for this problem?
hjlf

Answer:

m > 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

11 + m > 15

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Subtract 11 on both sides:                    m > 4

Here we see that any value <em>m</em> greater than 4 would work as a solution to the inequality.

6 0
2 years ago
HELP ASAP!!! PLEASE CHECK ALL OF THEM!
pochemuha

Answer:

2.

A. (P+h)(x)

2x/x+4 (x-1) + x/x-1 (x+4)

2x^2-1/x^2-4

+

X^2+4/x^2-4

= 3x^2+3/x^2-4

B. (F-g)(x)

X^2-7x+6-x - 6

= x^2 -8x

C. (Fg)(x)

(X^2-7x+6)(x-6)

= x^3-13x^2+48x-36

D. (H/p)(x)

X/x-1 / 2x/x+4

X/x-1 / x+4/2x

= X^2+4x/2x^2-2x

3.

A. (F+g)(3)

X^2+1 + x-4

3^2+1 + 3-4

10 -1

= 9

B. (f-g)(0)

X^2+1 - x-4

0+1 -0-4

1-4

= -3

C. (Fg)(-k)

(X^2+1) (x-4)

(-k^2+1) (-k-4)

K^3+4k^2-k-4

D. (F/g)(k-2)

X^2+1 /x-4

K-2^2+1 / k-2 -2

= K^2-4k+5 / k-4

Step-by-step explanation:

8 0
3 years ago
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