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dedylja [7]
1 year ago
9

Solve each equation. Round to the nearest ten-thousandth. Check your answers. 25²x⁺¹=144

Mathematics
1 answer:
djverab [1.8K]1 year ago
3 0

25^{2x+1}=144 => x = 0.272, by properties of logarithm.

<h3>What is Logarithm?</h3>
  • The opposite of exponentiation is the logarithm.
  • This indicates that the exponent to which a fixed number, base b, must be raised in order to obtain a specific number x, is represented by the logarithm of that number.
  • A number's natural logarithm is its logarithm to the base of the transcendental and irrational number e, which is roughly equivalent to 2.718281828459.

Given: 25^{2x+1}=144

Taking logarithm on both sides:

log (25^{2x+1}) = log (144)

=> (2x + 1) log (25) = log (144) (As log_b(a)^m = m (log_b(a)))

=> 2x + 1 = \frac{log144}{log25}

=> 2x + 1 = \frac{2.158}{1.397}

=> 2x + 1 = 1.544

=> 2x = 0.544

=> x = 0.272

Hence, 25^{2x+1}=144 => x = 0.272, by properties of logarithm.

To learn more about logarithms, refer to the link: brainly.com/question/25710806

#SPJ4

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It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi
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Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

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The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

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The designed life should be of 21,840 vehicle miles.

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