All categories

3 years ago

What is 9x-2?????????????

Mathematics

1 answer:

vitfil [10]3 years ago

3 0

Answer:

If you mean 9 x -2 it's -18

Step-by-step explanation:

You might be interested in

Given the equation

tatiyna

Answer:

A. Subtract x from both sides: (i.e. 5+x-12 = x-7 <--> 5-12 = -7)

This equation is identically true, so it holds no matter what x is.

B. This one is pretty self-explanatory

Step-by-step explanation:

u wrote the question wrongly the answer is in answer box

This question also my teacher gives me

hope it helps

8 0

2 years ago

8x^3-6x^2+13x-4<br> Please simplify this expression and tell me how u simplified it.

jeka94

This expression is already simplified.

5 0

2 years ago

If the car spends no time going 35 miles per hour, about how long would the trip take? Round the answer to the nearest hundredth

GrogVix [38]

What’s the car ride hour

7 0

3 years ago

Abigail starts work at 8:00 am and Zavier starts at 7:00 am. They both finish at the same time. If abigail works x hours, how ma

Tamiku [17]

X+1 Hours, because Zavier begins work an hour earlier than Abigail.

7 0

1 year ago

Read 2 more answers

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

2 years ago