What is 9x-2?????????????

1. The mean annual US household income is $72,641. Suppose that the standard deviation is $30,000. a. Find the probability that

valina [46]

Answer:

The answer is below

Step-by-step explanation:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. The z score is given as:

$z=\frac{x-\mu}{\sigma}\\\\where\ x=raw\ score,\mu=mean\ and\ \sigma=standard\ deviation \\\\For\ a\ sample\ size\ n: \\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }$

Given that μ = $72,641 and σ = $30,000.

a) x > $100000

$z=\frac{100000-72641}{30000}=0.91$

P(x > 100000) = P(z > 0.91) = 1 - 0.8186 = 0.1814

b) n = 5

x > $100000

$z=\frac{100000-72641}{30000/\sqrt{5} }=2.04$

P(x > 100000) = P(z > 2.04) = 1 - 0.9793 = 0.0207

c) n = 10

x > $100000

$z=\frac{100000-72641}{30000/\sqrt{10} }=2.88$

P(x > 100000) = P(z > 2.88) = 1 - 0.9980 = 0.002

4 0

2 years ago

What object has a definite beginning and a definite ending?

Andrew [12]

A line segment has a definite ending and beginning

8 0

3 years ago

dominic rides hus bike at a rate of 4 minutes per mile how many miles will it take him to ride 12 miles

earnstyle [38]

It would be 48 miles

7 0

3 years ago

Read 2 more answers

Prakash bought a new car at the dealership for $27,000. it is estimated that the value of the car will decrease 7% each year. wh

Dennis_Churaev [7]

The exponential function models the value v of the car after t years is V = 27000 * (0.93)^t

<h3>How to determine the exponential model?</h3>

The given parameters are:

Initial value, a = $27,000

Depreciation rate, r = 7%

The value of the car is then calculated as:

V = a * (1 -r)^t

Substitute known values

V = 27000 * (1 - 7%)^t

Evaluate the difference

V = 27000 * (0.93)^t

Hence, the exponential function models the value v of the car after t years is V = 27000 * (0.93)^t

Read more about exponential function at:

brainly.com/question/11464095

#SPJ1

6 0

1 year ago

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

3 years ago