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lianna [129]
2 years ago
7

Find the tangent of the angle indicated by each of the following right angle triangles.

Mathematics
1 answer:
Nataliya [291]2 years ago
4 0

Answer:

56.31 degrees

Step-by-step explanation:

6 = opposite and 4 = adjacent

Tan = opposite over adjacent

Tan(theta)=6/4

=56.30993247

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What is 5x+8y=14<br> 4x=24
Flauer [41]

Answer:

x = 6, y = -2

Step-by-step explanation:

24/4 = 6

x = 6

= (5x6)+8y=14

= 8y = 14 -30

8y = -16

y = -16/8

y = -2

Check: 5x6+8x-2= 14

5 0
2 years ago
the volume of a cube depends on the length of its sides.this can be written in function notation as v(s). what is the best inter
Sergeeva-Olga [200]

<u>Answer:</u>

Interpretation: A cube with sides of 4 units each has a volume of 64 units³.

<u>Explanation:</u>

As v(s) represents the volume of the cube, s represents the length of the sides.

∴ v(4) represents the volume of a cube with sides of  units, and the volume is 64 units³

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2 years ago
What two numbers multiply to 630 and add to -57
sveta [45]
-15 and -42 both add to -57 and multiply to 630 
5 0
3 years ago
Read 2 more answers
What is the perimeter of a square with a side whose length is x + 4?
Novosadov [1.4K]

Answer:

4x+16

Step-by-step explanation:

Just multiply x and 4 by 4 to get your answer.

4 0
3 years ago
Suppose that the time (in hours) required to repair a machine is an exponentially distributed random variable with mean 1/0.41/0
lbvjy [14]

Answer:

a) P(t>3)=0.30

b) P(t>10|t>9)=0.67

Step-by-step explanation:

We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.

The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.

The probabity that a repair time exceeds k hours can be written as:

P(t>k)=e^{-\lambda t }=e^{-0.4t}

(a) the probability that a repair time exceeds 3 hours?

P(t>3)=e^{-0.4*3}=e^{-1.2}= 0.30

(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?

The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.

In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.

P(t>10|t>9)=P(t>1)

P(k>1)=e^{-0.4*1}=0.67

6 0
3 years ago
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