We need to find the lowest common multiple of 6 and 8...and that number would be 24. So 24 days from March 5 is when they will both happen again.
So thats gonna make it March 29.
Answer:
as the cycle continues, you will always get 50 as the answer, since you are dividing both the numerator and the denominator with 10 in each expression. In other words, the 10:00 you divide the numerator which cancels out with the 10 you divide the denominator with. So the answer will always be 50 in each next expression.
Step-by-step explanation:
(I) 45÷90= 4500/90 = 50
(ii) 450÷9= 450/9 =50
(iii) 45÷0.9 = 45/0.9=50
(iv) 4.5 ÷ 0.09 = 45/0.09
starting with (I) 4500÷90 = 4500/90 =50
you divide the numerator and the denominator by 10 to get ; (ii) 450÷9 = 450/9 = 50
as the cycle continues you will always get 50 as the answer since you are dividing both the numerator and the denominator with 10 in each expression. In other words, the 10:00 you divide the numerator with cancels out with the 10 you divide the denominator with. So the answer will always be 50.
Answer:
B. $ 3094.01
Step-by-step explanation:
Given observations are,
$2894.21, $1777.15, $2144.77, $4096.37, $4046.29, $1786.37, $3296.69, $4086.27, $2784.22
Number of observations = 10,
Sum of the observations = 2894.21+1777.15+2144.77+4096.37+4046.29+1786.37+3296.69+4086.27+2784.22+4027.79 = 30940.13,
Hence,
Option 'B' is correct.
He rounded it to the nearest hundred, not ten. Ten would be 560.
Hope this helps!
Let us assume the two numbers to be "x" and "y".
Then
xy = - 24
x = - (24/y)
And
x + y = 2
Putting the value of x from the first equation in the second equation, we get
x + y = 2
- (24/y) + y = 2
- 24 + y^2 = 2y
y^2 - 2y - 24 = 0
y^2 - 6y + 4y - 24 = 0
y(y - 6) + 4(y - 6) = 0
(y - 6) (y + 4) = 0
When
y - 6 = 0
y = 6
Then
x + y = 2
x + 6 = 2
x = 2 - 6
= -4
And when
y + 4 = 0
y = -4
Then
x + y = 2
x - 4 = 2
x = 2 + 4
= 6
So the two unknown numbers are -4 and 6.
