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2 years ago

Determine the equation of the circle graphed below.

Mathematics

1 answer:

MrMuchimi2 years ago

7 0

Equation of a Circle: (x - h)^2 + (y - k)^2 = r^2

(h, k) = center of the circle

r = radius of the circle

Center = (2, 0)

Radius = 7

Equation: (x - 2)^2 + (y - 0)^2 = 49

Answer: (x - 2)^2 + y^2 = 49

Hope this helps!

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valina [46]

Answer:

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3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

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And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

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$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

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B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

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v0 = initial velocity = 0,

t = time of motion,

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Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

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almond37 [142]

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