Answer:
a. Variable term
b. Variable term
Explanation:
a) We were given the algebraic expression:
The first term of the algebraic expression is:
The first term is a variable term
The variable is "y" and its coefficient is "-5"
b) We were given the algebraic expression:
The second term of the algebraic expression is:
The second term is a variable term
The variable is "b" and the coefficient is "-6"
Subtract 5 from both sides
a/-8 = 4/7 - 5
simplify 4/7 - 5 to 31/-7
a/-8 = 31/-7
multiply both sides by 8
-a = 31/-7 x 8
simplify 31/7 x 8 to 248/7
-a = 248/7
multiply both sides by -1.
The answer is a = 248/7
The words are the explanations of the steps and the dark bolded words are the work shown for each step.
Given, To make a strawberry shortcake for one person, we need :
▪︎
cup of strawberry
▪︎one shortbread biscuit
Quantity of strawberries Elisa has = 3 cups
Number of shortbread biscuits she has = 12
Number of shortcakes she can make :
Thus, Elisa can serve strawberry shortcakes to 9 people.
With 12 dozen shortbread biscuits she can serve 12 people.
Quantity of strawberries needed to serve 12 people :
<h3>○=> Therefore :</h3>
▪︎Elisa can serve strawberry shortcakes to <u>9 people</u>.
▪︎Elisa will need <u>4 cups of strawberries</u> if she wants to use all dozen shortbread biscuits.
Answer:
2.38 miles
Step-by-step explanation:
From Given diagram:
In ΔABC,
AC=2.5 miles
BC= 3.7 miles
∠BCA= 39.4°
Now as we have two sides and an angle, using law of cosines to find the third side:
c= √(a^2+b^2-2abcosα
AB=√(AC)^2 + (BC)^2 - 2(AC)(BC)cosα
=√(2.5)^2 + (3.7)^2 - 2(2.5)(3.7)cos(39.4°)
=√(2.5)^2 + (3.7)^2 - 2(2.5)(3.7)(0.77)
=√(5.695)
= 2.38 !
Answer:
4851 ways
Step-by-step explanation:
The fish have 3 choices. They can make it above, below, or though the pipe. Keep in mind there are 100 fish total:
group 1 + group 2 + group 3 = 100
If we keep group 3 (the fish that swim below the pipe) constant, say 1, and increment the other two (group 2 starting off at 1) we find 98 possibilities.
98 + 1 + 1 = 100,
97 + 2 + 1 = 100,
96 + 3 + 1 = 100
. . . 98 possibilities
Now we take group 1 as one greater (1 + 1 = 2) and then start incrementing group 2 starting from 1 as done before. So 97 + 2 + 1 = 100. Followed by 96 + 3 + 1, 95 + 4 + 1...97 possibilities
If we continue this pattern, we have 98 + 97 + 96... + 1 total possibilities to partition this school of fish.
98 + 97 + 96... + 1,
Sum = n(n + 1)/2 = 98(98 + 1)/2 = 98(99)/2 = 4851
