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Alexus [3.1K]
2 years ago
13

The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his

bike in the five days?
Day Time (minutes)
1 45
2 109
3 51
4 121
5 38
Mathematics
1 answer:
Zinaida [17]2 years ago
8 0

Answer:98.9276

Step-by-step explanation:

The table displays the amount of time, in minutes, Jordan rode his bike for five days.  How many total hours did Jordan ride his bike in the five days?  ​​DayTime (minutes)​​11  ​4545  ​22  ​109109  33 ​5151 ​​44  ​121121  ​55  ​3838  ​Jordan rode his bike  total hours in the five days.

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The coldest temperature ever recorded on Earth is 135.8°F below 0, recorded
Rom4ik [11]

Answer:

-269.8

Step-by-step explanation:

Below 0 is negative.

Them do -135.8 - 134.

8 0
2 years ago
Please actually help because my anxiety sucks. "Joe is seven years younger than Bill. The sum of their ages is less than 49. At
kherson [118]
Joe is at most 20 and Bill would be at most 27 because it has to be less than 49 combined
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2 years ago
Is this right? Question isn’t below!
Angelina_Jolie [31]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amoun
zmey [24]
Alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm
7 0
3 years ago
The legs of the right triangle have Links of 28 metres and 21 metres
GarryVolchara [31]
If we're trying to find the hypotenuse we'll take the \sqrt{28^{2}+ 21^{2}  }
Getting 35.

35
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2 years ago
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