It would be 10 bc u times both by two
The velocity of the particle is given by

Since
and
, we get


Similarly, the position function is obtained via

We know
and we're told that
, so


making the answer A.
Answer:
67
Step-by-step explanation:
A and b can do a piece of work in 12 days. If a alone have to finish the job among b and c so
A and b=12
A (24 days alone without b)
So if b and c 15 days and c 20 days. If a have to do all I would add 24 and 15 and 20 which would be 59 days
60m there's 60 minutes in an hour.