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2 years ago

If m∠ACB = 36, find the area of the shaded sector.

Mathematics

1 answer:

velikii [3]2 years ago

4 0

Answer: 7.85

Explanation: The formula you would use to find the area for the shaded sector is

degree / 360 • 3.14 • r^2

36 / 360 • 3.14 • 5^2

You would square it because we’re looking for area.

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VashaNatasha [74]

Answer:

A. 4

Step-by-step explanation:

First, we can try the first option. 2/4 is equivalent to 6/12 when you multiply the fraction by 3 to get a common denominator. Since 6/12 is larger than 4/12, and the question has 1 answer, 4 is the only value that satisfices the statement and is the answer.

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2 years ago

A fence is 10 ft wide by 10 ft long. If posts are placed 2 feet apart how many posts are needed?

yuradex [85]

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2 years ago

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3 years ago

Read 2 more answers

90°<br> 46°<br> Find the unknown. angle measure<br> please help :)

Ganezh [65]

Answer:

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Step-by-step explanation:

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2 years ago

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When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

$P = 0.6*0.2 = 0.12$

There is a 12% probability that only Alice watches TV tomorrow.

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3 years ago