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vampirchik [111]
2 years ago
7

Help! im doing a gooru question but i dont know how to do it

Mathematics
1 answer:
Natalija [7]2 years ago
6 0

Answer:

4a^{10}

Step-by-step explanation:

\textsf{Given expression}:

(a^2)^5 \cdot 4^3 \cdot 4^{-2}

\textsf{Apply radical rule} \quad a^b \cdot a^c=a^{b+c}:

\implies (a^2)^5 \cdot 4^{3+(-2)}

\implies (a^2)^5 \cdot 4^1

\implies (a^2)^5 \cdot 4

\textsf{Apply radical rule} \quad (a^b)^c=a^{bc}:

\implies a^{2 \cdot 5} \cdot 4

\implies a^{10} \cdot 4

\textsf{Final solution}:

\implies 4a^{10}

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An airplane leaves an airport at 9:00 p.M. With a heading of 270 and a speed of 610 mph. At 10:00 p.M. The pilot changes the he
timama [110]

Answer:

2330.51 miles

Step-by-step explanation:

Given that the speed of the airplane = 610 mph.

The airplane leaves an airport at 9:00 P.M. with a heading of 270 degrees and at 10:00 P.M., the pilot changes the heading to 310 degrees.

So, for 1 hour the plane is heading at 270 degrees and for 3 hours, from 10:00 p.m to 1:00 a.m, the plane is heading at 310 degrees as shown in the figure.

As, distance = time x speed, so

The distance covered at 270 degrees, d_1 = 1\times610=610 miles.

The distance covered at 310 degrees, d_2 = 3\times610=1830 miles.

Total distance covered, d, is the magnitude of the sum of vectors \vec{d_1} and \vec{d_2} as shown in the figure.

The angle between the vectors \vec{d_1} and \vec{d_2}, \theta=310-270=40 degree.

Magnitude of sum of the vectors \vec{d_1} and \vec{d_2},

d= \sqrt{|\vec{d_1}|^2+|\vec{d_2}|^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\theta} \\\\\Rightarrow d=\sqrt{610^2+1830^2+2|\vec{d_1}|\;|\vec{d_2}|\cos\(40^{\circ})}

\Rightarrow d=2330.51 miles

Hence, at 1:00 a.m, the airplane is at a distance of 2330.51 miles from the airport.

4 0
3 years ago
PLZ!!! I NEED AN ANSWER!!! What is the Vertex? y = 3x^ 2 − 6x − 2
coldgirl [10]
Vertex is: 1, -5

Explanation:

5 0
2 years ago
Solve each system by substitution <br> 5x + 7y = -23<br> Y = -2x - 11
Alenkasestr [34]

Answer:

x = −6

Explanation:

5x + 7y = -23

Y = -2x - 11

Substitute -2x - 11 for y in 5x + 7y = -23

5x + 7(−2x − 11) = −23

Simplify both sides of the equation

5x + 7(−2x − 11) = −23

5x + (7)(−2x ) + (7)(−11) = −23 (Distribute)

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(5x + −14x) + (−77) = −23 (Combine Like Terms)

−9x + −77 = −23

−9x − 77 = −23

Add 77 to both sides

−9x − 77 + 77 = −23 + 77

−9x = 54

Divide both sides by -9

−9x / -9 = 54 / -9

x = -6

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3 years ago
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dlinn [17]
Exact Form:
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