Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
Answer:
Step-by-step explanation:
Given:
Solving for 
:
Answer: A , B, C, E
Step-by-step explanation:√4 = 2√5 = 2.24√5.5 = 2.36√6 = 2.45√8 = 2.83√9 = 3
A)√5 < 2.3<√62.24 < 2.3 < 2.45 True
B)√5 < 2.4<√62.24 < 2.4 < 2.45 True
C)√4 < √5 < √5.52 < 2.24 < 2.36 True
D)√8 < 3 < √92.83 < 3 < 3 False
E)√8 < 2.9 < √92.83 < 2.9 < 3 True
F)√4 < 4.5 < √52 < 4.5 < 2.24 False
Ax + By = C....standard form
0.05n + 0.25q = 3.80....I just used the variables (n) for nickels and (q) for quarters....but u could use x and y if u want to. But if u do this, be sure and label ur variables
