Answer:
f^-1 (x) = 1+ln( (x-3)/2)
Step-by-step explanation:
hello :
let f(x) = y so : y = 2e^(x-1) +3
calculate x : e^(x-1) = (y-3)/2
for : y-3 > 0 : x-1 = ln( (y-3)/2) so : x= 1+ln( (y-3)/2)
If(x)= 2e^(x-1) +3 , what is f^-1 (x) = 1+ln( (x-3)/2)
Answer:
1 time
Step-by-step explanation:
You can see the graph I've attached below.
They both meet just once at (-1, -2).
Answer:
0.27 ; 2.07 ; 7.02 ; 7.2 ; 27.2
Answer:
2 1⁄4 or 2.25
Step-by-step explanation:






Hope it helps you!!
#IndianMurga(. ❛ ᴗ ❛.)