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3 years ago

1/7 divided by what gives you 14

1 answer:

5 0

(1/7) / x = 14 ....multiply both sides by x, this eliminates the x on the left
1/7 = 14x...divide both sides by 14
(1/7) / 14 = x
1/7 * 1/14 = x
1/98 = x <===

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1.2x-4y=28 solve for y

Gnesinka [82]

2x -4y= 28
⇒ -4y= 28 -2x
⇒ y= (28 -2x)/ (-4)
⇒ y= 28/(-4) -(2x)/ (-4)
⇒ y= -7 + 1/2x

The final answer is y= -7 + 1/2x~

4 0

3 years ago

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3 years ago

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9966 [12]

Answer:

D) b = $\frac{S-2ac}{2a + 2c}$

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = $\frac{S-2ac}{2(a + c)}$

Finally, multiply out the denominator:

b = $\frac{S-2ac}{2a + 2c}$

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3 years ago

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mixas84 [53]

Answer:

Step-by-step explanation:

2. 9a +4c=43

a+c=7

The total tickets for adults and children = 7 (a+c =7) 7 people in all

price for adult = $9 (9a) Price per child =$4 (4c)

total price =$ 43

9a +7c = 43

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

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1 year ago