If x = 14 cm, y = 7 cm, and z = 8 cm, what is the surface area of the figure?

Mathematics

1 answer:

Nat2105 [25]2 years ago

8 0

Formula for sufrace area of rectangular prisms: S= 2 (lw + lh + wh)

for the first prism, x=14, plug 14 into 2(x)--> 2(14)=28

7,8,28

S= 2 [7(8)+7(28)+8(28)]

S= 2 (28+196+224)

S= 2(448)

S= 896

for the second prism, x is just 14

7,8,14

S= 2 [7(8)+7(14)+8(14)]

S= 2 (28+98+112)

S= 2(238)

S= 476

Add the two sufrace areas we found and the answer will be

D) S= 1,372

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Can someone please explain how to solve this? And give me the answer?! THANK U !

Lyrx [107]

we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.

$\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76$