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geniusboy [140]
3 years ago
10

I need help with these two equations

Mathematics
1 answer:
Ivan3 years ago
7 0

for these you need to rearrange the equations and do substitutions.

 #3 = if x+y=5 then you know x = 5-y

 now substitute that equation for x in the 2nd one so x + 2y = 8 becomes

5-y + 2y = 8 2y - y becomes 1y which becomes y then subtract 5 from each side to get y =3

now replace y with 3 in the first equation x = 5-3 so x = 2 

 so (2,3) is the answer


 same type of work for #4

2x-y=6 ,S0 y = 2X+6

 so now you have 4x+2(2x+6)=-4

that becomes 4x +4x+12 = -4

8x+8 = 1, x =1

y = 2(1)-6 = -4

 so answer is (1,-4)

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Answer:

An equation relating x and y is:

y = 3/4x - 5.5

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

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Given the points

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Taking any two points let say A(6, -1), and B(10, 2) to determine the slope

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(6,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:2\right)

m=\frac{2-\left(-1\right)}{10-6}

Refine

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We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = -5.5

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y = mx+b

y = 3/4x + (-5.5)

y = 3/4x - 5.5

Therefore, an equation relating x and y is:

y = 3/4x - 5.5

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like bro i havent been paying attention to school that I havent learn stuff and I'm in 9th grade

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