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Fynjy0 [20]
1 year ago
7

Which of the following is the function represented

Mathematics
1 answer:
ale4655 [162]1 year ago
5 0

Answer:

the last (4th) option

Step-by-step explanation:

the easiest way to find the right answer :

which of the 4 answers would deliver infinity for x = 5 ?

and that is only answer 4, as x = 5 creates 0 in the denominator of the fraction, which leads to the infinity break at that point in the functional curve.

other indications :

the smaller x, the more the denominator goes to -infinity, and the bigger x, the more the denominator goes to +infinity.

and that means the whole fraction goes to 0. and we are left for the function limit with the constant added at the end of the function.

looking at the graph, this has to be +3.

and again, only the 4th answer has "+3" at the end.

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Guys 20 points please helpppp​
Igoryamba

Answer:

i would say your right

Step-by-step explanation:

8 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

6 0
2 years ago
On Tuesday Conrad had 3 times as many sales as on Monday. On Wednesday, he had 9 times as many sales as on Monday. Over the thre
Vlad1618 [11]

Answer:

Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

Step-by-step explanation:

Let x be the no. of sales on Monday

We are given that On Tuesday Conrad had 3 times as many sales as on Monday.

So, Conrad had sales on Tuesday = 3x

We are also given that On Wednesday, he had 9 times as many sales as on Monday.

So, Conrad had sales on Wednesday = 9x

Over the three days, he had a total of 728 sales

So, x+3x+9x=728

13x=728

x=\frac{728}{13}

x=56

Conrad had sales on Tuesday = 3x =3(56)=168

Conrad had sales on Wednesday = 9x=9(56)=504

Hence Conrad had 56 sales on Monday , 168 sales on Tuesday and 504 sales on Wednesday.

7 0
2 years ago
Can you help me please ​
Volgvan
$5000 I think should be right
8 0
2 years ago
What’s the Value of x?
denpristay [2]
X will be 8.49
the other side is 6 too
6 0
3 years ago
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