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rewona [7]
2 years ago
7

Triangle BDC is isosceles

Mathematics
1 answer:
Ganezh [65]2 years ago
6 0

ZCAB angle is congruent to ZBAD

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When making a long distance call from a certain pay phone, the first three minutes of a call cost $3.00. afterthat, each additio
motikmotik
3 + 0.45*M<=8,40. Notice the equal, because you may use all the money. Then, rearranging: M<=(8.40-3)/0.45= 12, so M<=12. Now, obviously time is positive, so you may end saying 0<=M<=12, with M=0 meaning no call! :)
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3 years ago
Given: ∠KJL and ∠KML intercept arc KL. Prove: m∠KJL = m∠KML
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I think it proved by the arc intercepting kl making it an interior alternate angle which means it equal to each other
 
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4 years ago
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Factor completely 3x2 - 21.
VMariaS [17]
3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go.  But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
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3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.
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3 years ago
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Find the cosine of the angle between the planes x+y+z=0 and 4x+3y+z=1.<br><br> Answer: cosθ=
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The angle between the planes is the same as the angle between their normal vectors, which are

<em>n</em><em>₁</em> = ⟨1, 1, 1⟩

<em>n</em><em>₂</em> = ⟨4, 3, 1⟩

The angle <em>θ</em> between the vectors is such that

⟨1, 1, 1⟩ • ⟨4, 3, 1⟩ = ||⟨1, 1, 1⟩|| ||⟨4, 3, 1⟩|| cos(<em>θ</em>)

Solve for cos(<em>θ</em>) :

4 + 3 + 1 = √(1² + 1² + 1²) √(4² + 3² + 1²) cos(<em>θ</em>)

8 = √3 √26 cos(<em>θ</em>)

cos(<em>θ</em>) = 8/√78

4 0
3 years ago
What are the values of x and y?
Ede4ka [16]

Step-by-step explanation:

In figure:

∠PRT+∠RTP+∠TPR=180

O

(angle sum property of triangle)

⇒x+(180

O

−∠RTQ)+60

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=180

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(linear pair)

⇒x+(180

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−97

0

)+60

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=180

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⇒x=31

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Now, ∠PRT+∠TRQ+∠QRS=180

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(angle of straight line)

⇒x+48

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+y=180

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⇒31

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+48

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+y=180

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⇒y=101

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3 0
2 years ago
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