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rewona [7]
2 years ago
7

Triangle BDC is isosceles

Mathematics
1 answer:
Ganezh [65]2 years ago
6 0

ZCAB angle is congruent to ZBAD

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A triangle with the coordinates X(3, 2), Y(5, -1), and Z(-2, 3) is reflected across both the x- and y-axes. The coordinates afte
nata0808 [166]

Answer:

The coordinates of the reflected triangle are X'(x,y) = (-3,-2), Y' (x,y) = (-5,1) and Z'(x,y) = (2,-3).

Step-by-step explanation:

Let be a point (a,b)\in\mathbb{R}^{2}, reflections across x- and y-axes are represented by the following operations:

x-Axis reflection:

d = d'

b - 0 = 0 - b'

b' = -b

y-Axis reflection:

d = d'

a - 0 = 0 - a'

a' = -a

If we know that X (x,y) = (3,2), Y(x,y) = (5,-1) and Z (x,y) = (-2, 3), the coordinates after both reflections are, respectively:

X'(x,y) = (-3,-2)

Y' (x,y) = (-5,1)

Z'(x,y) = (2,-3)

The coordinates of the reflected triangle are X'(x,y) = (-3,-2), Y' (x,y) = (-5,1) and Z'(x,y) = (2,-3).

8 0
3 years ago
What is the equation in point slope form of the line that passes through the point (−1, −3) and has a slope of 4?
Firlakuza [10]

Answer:

(y-(-3))=4(x-(-1))

Step-by-step explanation:

formula for point slope form is:

y-y1=m(x-x1)

just plug in numbers from the point (-1, -3) for x1 and y1. The slope 4, would plug into m.

6 0
3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Hi im dont even know why I posted this lol im bored
tiny-mole [99]

Answer:

free answer

Step-by-step explanation:

it is free

3 0
3 years ago
Read 2 more answers
PLZZZZ HELP What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?
earnstyle [38]

\bf 3y=-4x+2\implies y=\cfrac{-4x+2}{3} \\\\\\ y=\stackrel{\stackrel{slope}{\downarrow }}{-\cfrac{4}{3}}x+\cfrac{2}{3}\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}


so the slope of that line above is really -4/3, now


\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{+\cfrac{3}{4}\implies \blacktriangleright \cfrac{3}{4} \blacktriangleleft}}

6 0
3 years ago
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