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igor_vitrenko [27]
2 years ago
15

What is the equation of a parabola if the vertex is (1, 4) and the directrix is located at y = 7?

Mathematics
1 answer:
Oksana_A [137]2 years ago
4 0

According to the vertex and the directrix of the given parabola, the equation is:

y = \frac{3}{4}(x - 1)^2 + 4

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

The directrix is at y = k + 4a.

In this problem, the vertex is (1,4), hence:

h = 1, k = 4

The directrix is at y = 7, hence:

4 + 4a = 7

a = \frac{3}{4}

Hence, the equation is:

y = a(x - h)^2 + k

y = \frac{3}{4}(x - 1)^2 + 4

More can be learned about the equation of a parabola at brainly.com/question/26144898

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Zoom in to see the question plzzz help!!!
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Answer:

\huge\boxed{\boxed{IV}}

Step-by-step explanation:

Given:

x>0

Which means

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y<0

Which means

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ig -1,-2,-3,-4,-5.........

So according to the question

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