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igor_vitrenko [27]
2 years ago
15

What is the equation of a parabola if the vertex is (1, 4) and the directrix is located at y = 7?

Mathematics
1 answer:
Oksana_A [137]2 years ago
4 0

According to the vertex and the directrix of the given parabola, the equation is:

y = \frac{3}{4}(x - 1)^2 + 4

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)^2 + k

In which a is the leading coefficient.

The directrix is at y = k + 4a.

In this problem, the vertex is (1,4), hence:

h = 1, k = 4

The directrix is at y = 7, hence:

4 + 4a = 7

a = \frac{3}{4}

Hence, the equation is:

y = a(x - h)^2 + k

y = \frac{3}{4}(x - 1)^2 + 4

More can be learned about the equation of a parabola at brainly.com/question/26144898

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The land area of the earth is 57,505,708 square miles. To the nearest tenth, how much longer is the land of Asia than North Amer
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Read 2 more answers
(2, -4), (x, y) , A , and B all lie on the line. Find an equation relating x and y.​
frutty [35]

Answer:

An equation relating x and y is:

y = 3/4x - 5.5

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the points

(2, -4), (x, y), A(6, -1), and B(10, 2)

Taking any two points let say A(6, -1), and B(10, 2) to determine the slope

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(6,\:-1\right),\:\left(x_2,\:y_2\right)=\left(10,\:2\right)

m=\frac{2-\left(-1\right)}{10-6}

Refine

m=\frac{3}{4}

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

From the graph, it is clear

at x = 0, y = -5.5

Thus, the y-intercept b = -5.5

Thus, substituting b = -5.5 and m = 3/4 in the slope-intercept form of the line equation

y = mx+b

y = 3/4x + (-5.5)

y = 3/4x - 5.5

Therefore, an equation relating x and y is:

y = 3/4x - 5.5

8 0
3 years ago
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